At 10 20, Howard left Town Z for Town A, driving at a speed of 60 km/h. At 11 20, Asher also left Town Z for Town A driving at a certain speed. Both of them did not change their speed throughout the journey. At 14 20, both of them passed a museum that was 120 km away from Town A. How many minutes earlier did Asher reach Town A than Howard?

Distance that Howard travelled
= 4 x 60
= 240 km

Distance between Town Z and Town A
= 240 + 120
= 360 km

Since Asher passed the museum at the same time as Howard, it means that Asher travelled 240 km in 3 hours.

Asher's speed during the journey
= 240 ÷ 3
= 80 km/h

Duration that Asher took to reach Town A after passing the museum
= 120 ÷ 80
= 1.5 h

Duration that Howard took to reach Town A after passing the museum
= 120 ÷ 60
= 2 h

Difference between the time they took to reach Town A
= 2 - 1.5
= 0.5 h

1 h = 60 min
0.5 h = 0.5 x 60 = 30 min

Asher reached Town A 30 minutes earlier than Howard.

Answer(s): 30 min