At 11 25, Andy left Town Q for Town R, driving at a speed of 84 km/h. At 13 25, Paul also left Town Q for Town R driving at a certain speed. Both of them did not change their speed throughout the journey. At 15 25, both of them passed a boutique that was 252 km away from Town R. How many minutes earlier did Paul reach Town R than Andy?

Distance that Andy travelled
= 4 x 84
= 336 km

Distance between Town Q and Town R
= 336 + 252
= 588 km

Since Paul passed the boutique at the same time as Andy, it means that Paul travelled 336 km in 2 hours.

Paul's speed during the journey
= 336 ÷ 2
= 168 km/h

Duration that Paul took to reach Town R after passing the boutique
= 252 ÷ 168
= 1.5 h

Duration that Andy took to reach Town R after passing the boutique
= 252 ÷ 84
= 3 h

Difference between the time they took to reach Town R
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Paul reached Town R 90 minutes earlier than Andy.

Answer(s): 90 min