At 11 50, Peter left Town R for Town S, driving at a speed of 62 km/h. At 14 50, Caden also left Town R for Town S driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 50, both of them passed a park that was 186 km away from Town S. How many minutes earlier did Caden reach Town S than Peter?

Distance that Peter travelled
= 5 x 62
= 310 km

Distance between Town R and Town S
= 310 + 186
= 496 km

Since Caden passed the park at the same time as Peter, it means that Caden travelled 310 km in 2 hours.

Caden's speed during the journey
= 310 ÷ 2
= 155 km/h

Duration that Caden took to reach Town S after passing the park
= 186 ÷ 155
= 1.2 h

Duration that Peter took to reach Town S after passing the park
= 186 ÷ 62
= 3 h

Difference between the time they took to reach Town S
= 3 - 1.2
= 1.8 h

1 h = 60 min
1.8 h = 1.8 x 60 = 108 min

Caden reached Town S 108 minutes earlier than Peter.

Answer(s): 108 min