At 11 10, Paul left Town B for Town C, driving at a speed of 77 km/h. At 13 10, Fabian also left Town B for Town C driving at a certain speed. Both of them did not change their speed throughout the journey. At 15 10, both of them passed a cafe that was 231 km away from Town C. How many minutes earlier did Fabian reach Town C than Paul?

Distance that Paul travelled
= 4 x 77
= 308 km

Distance between Town B and Town C
= 308 + 231
= 539 km

Since Fabian passed the cafe at the same time as Paul, it means that Fabian travelled 308 km in 2 hours.

Fabian's speed during the journey
= 308 ÷ 2
= 154 km/h

Duration that Fabian took to reach Town C after passing the cafe
= 231 ÷ 154
= 1.5 h

Duration that Paul took to reach Town C after passing the cafe
= 231 ÷ 77
= 3 h

Difference between the time they took to reach Town C
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Fabian reached Town C 90 minutes earlier than Paul.

Answer(s): 90 min