At 13 55, Justin left Town Y for Town Z, driving at a speed of 63 km/h. At 15 55, Simon also left Town Y for Town Z driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 55, both of them passed a salon that was 189 km away from Town Z. How many minutes earlier did Simon reach Town Z than Justin?
Duration that Justin travelled from 13 55 to 18 55 = 5 h
Distance that Justin travelled
= 5 x 63
= 315 km
Distance between Town Y and Town Z
= 315 + 189
= 504 km
Since Simon passed the salon at the same time as Justin, it means that Simon travelled 315 km in 3 hours.
Simon's speed during the journey
= 315 ÷ 3
= 105 km/h
Duration that Simon took to reach Town Z after passing the salon
= 189 ÷ 105
= 1.8 h
Duration that Justin took to reach Town Z after passing the salon
= 189 ÷ 63
= 3 h
Difference between the time they took to reach Town Z
= 3 - 1.8
= 1.2 h
1 h = 60 min
1.2 h = 1.2 x 60 = 72 min
Simon reached Town Z 72 minutes earlier than Justin.
Answer(s): 72 min