At 14 30, Brandon left Town F for Town G, driving at a speed of 76 km/h. At 17 30, Cody also left Town F for Town G driving at a certain speed. Both of them did not change their speed throughout the journey. At 20 30, both of them passed a boutique that was 228 km away from Town G. How many minutes earlier did Cody reach Town G than Brandon?

Distance that Brandon travelled
= 6 x 76
= 456 km

Distance between Town F and Town G
= 456 + 228
= 684 km

Since Cody passed the boutique at the same time as Brandon, it means that Cody travelled 456 km in 3 hours.

Cody's speed during the journey
= 456 ÷ 3
= 152 km/h

Duration that Cody took to reach Town G after passing the boutique
= 228 ÷ 152
= 1.5 h

Duration that Brandon took to reach Town G after passing the boutique
= 228 ÷ 76
= 3 h

Difference between the time they took to reach Town G
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Cody reached Town G 90 minutes earlier than Brandon.

Answer(s): 90 min