At 14 10, Will left Town B for Town C, driving at a speed of 62 km/h. At 17 10, Luis also left Town B for Town C driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 10, both of them passed a cinema that was 186 km away from Town C. How many minutes earlier did Luis reach Town C than Will?

Distance that Will travelled
= 5 x 62
= 310 km

Distance between Town B and Town C
= 310 + 186
= 496 km

Since Luis passed the cinema at the same time as Will, it means that Luis travelled 310 km in 2 hours.

Luis's speed during the journey
= 310 ÷ 2
= 155 km/h

Duration that Luis took to reach Town C after passing the cinema
= 186 ÷ 155
= 1.2 h

Duration that Will took to reach Town C after passing the cinema
= 186 ÷ 62
= 3 h

Difference between the time they took to reach Town C
= 3 - 1.2
= 1.8 h

1 h = 60 min
1.8 h = 1.8 x 60 = 108 min

Luis reached Town C 108 minutes earlier than Will.

Answer(s): 108 min