At 10 30, Luke left Town A for Town B, driving at a speed of 86 km/h. At 12 30, Daniel also left Town A for Town B driving at a certain speed. Both of them did not change their speed throughout the journey. At 14 30, both of them passed a park that was 258 km away from Town B. How many minutes earlier did Daniel reach Town B than Luke?

Distance that Luke travelled
= 4 x 86
= 344 km

Distance between Town A and Town B
= 344 + 258
= 602 km

Since Daniel passed the park at the same time as Luke, it means that Daniel travelled 344 km in 2 hours.

Daniel's speed during the journey
= 344 ÷ 2
= 172 km/h

Duration that Daniel took to reach Town B after passing the park
= 258 ÷ 172
= 1.5 h

Duration that Luke took to reach Town B after passing the park
= 258 ÷ 86
= 3 h

Difference between the time they took to reach Town B
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Daniel reached Town B 90 minutes earlier than Luke.

Answer(s): 90 min