At 12 45, Ivan left Town Z for Town A, driving at a speed of 69 km/h. At 15 45, Zeph also left Town Z for Town A driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 45, both of them passed a bistro that was 207 km away from Town A. How many minutes earlier did Zeph reach Town A than Ivan?

Distance that Ivan travelled
= 6 x 69
= 414 km

Distance between Town Z and Town A
= 414 + 207
= 621 km

Since Zeph passed the bistro at the same time as Ivan, it means that Zeph travelled 414 km in 3 hours.

Zeph's speed during the journey
= 414 ÷ 3
= 138 km/h

Duration that Zeph took to reach Town A after passing the bistro
= 207 ÷ 138
= 1.5 h

Duration that Ivan took to reach Town A after passing the bistro
= 207 ÷ 69
= 3 h

Difference between the time they took to reach Town A
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Zeph reached Town A 90 minutes earlier than Ivan.

Answer(s): 90 min