At 12 35, Zeph left Town V for Town W, driving at a speed of 88 km/h. At 14 35, Peter also left Town V for Town W driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 35, both of them passed a bakery that was 264 km away from Town W. How many minutes earlier did Peter reach Town W than Zeph?

Distance that Zeph travelled
= 4 x 88
= 352 km

Distance between Town V and Town W
= 352 + 264
= 616 km

Since Peter passed the bakery at the same time as Zeph, it means that Peter travelled 352 km in 2 hours.

Peter's speed during the journey
= 352 ÷ 2
= 176 km/h

Duration that Peter took to reach Town W after passing the bakery
= 264 ÷ 176
= 1.5 h

Duration that Zeph took to reach Town W after passing the bakery
= 264 ÷ 88
= 3 h

Difference between the time they took to reach Town W
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Peter reached Town W 90 minutes earlier than Zeph.

Answer(s): 90 min