At 10 20, Jack left Town B for Town C, driving at a speed of 72 km/h. At 12 20, Dylan also left Town B for Town C driving at a certain speed. Both of them did not change their speed throughout the journey. At 14 20, both of them passed a clinic that was 216 km away from Town C. How many minutes earlier did Dylan reach Town C than Jack?

Distance that Jack travelled
= 4 x 72
= 288 km

Distance between Town B and Town C
= 288 + 216
= 504 km

Since Dylan passed the clinic at the same time as Jack, it means that Dylan travelled 288 km in 2 hours.

Dylan's speed during the journey
= 288 ÷ 2
= 144 km/h

Duration that Dylan took to reach Town C after passing the clinic
= 216 ÷ 144
= 1.5 h

Duration that Jack took to reach Town C after passing the clinic
= 216 ÷ 72
= 3 h

Difference between the time they took to reach Town C
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Dylan reached Town C 90 minutes earlier than Jack.

Answer(s): 90 min