At 12 50, Jack left Town B for Town C, driving at a speed of 75 km/h. At 13 50, Albert also left Town B for Town C driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 50, both of them passed a boutique that was 150 km away from Town C. How many minutes earlier did Albert reach Town C than Jack?

Distance that Jack travelled
= 4 x 75
= 300 km

Distance between Town B and Town C
= 300 + 150
= 450 km

Since Albert passed the boutique at the same time as Jack, it means that Albert travelled 300 km in 3 hours.

Albert's speed during the journey
= 300 ÷ 3
= 100 km/h

Duration that Albert took to reach Town C after passing the boutique
= 150 ÷ 100
= 1.5 h

Duration that Jack took to reach Town C after passing the boutique
= 150 ÷ 75
= 2 h

Difference between the time they took to reach Town C
= 2 - 1.5
= 0.5 h

1 h = 60 min
0.5 h = 0.5 x 60 = 30 min

Albert reached Town C 30 minutes earlier than Jack.

Answer(s): 30 min