At 11 25, Michael left Town D for Town E, driving at a speed of 78 km/h. At 14 25, George also left Town D for Town E driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 25, both of them passed a bistro that was 234 km away from Town E. How many minutes earlier did George reach Town E than Michael?

Distance that Michael travelled
= 6 x 78
= 468 km

Distance between Town D and Town E
= 468 + 234
= 702 km

Since George passed the bistro at the same time as Michael, it means that George travelled 468 km in 3 hours.

George's speed during the journey
= 468 ÷ 3
= 156 km/h

Duration that George took to reach Town E after passing the bistro
= 234 ÷ 156
= 1.5 h

Duration that Michael took to reach Town E after passing the bistro
= 234 ÷ 78
= 3 h

Difference between the time they took to reach Town E
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

George reached Town E 90 minutes earlier than Michael.

Answer(s): 90 min