At 13 55, Paul left Town D for Town E, driving at a speed of 80 km/h. At 16 55, Tommy also left Town D for Town E driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 55, both of them passed a boutique that was 240 km away from Town E. How many minutes earlier did Tommy reach Town E than Paul?
Duration that Paul travelled from 13 55 to 19 55 = 6 h
Distance that Paul travelled
= 6 x 80
= 480 km
Distance between Town D and Town E
= 480 + 240
= 720 km
Since Tommy passed the boutique at the same time as Paul, it means that Tommy travelled 480 km in 3 hours.
Tommy's speed during the journey
= 480 ÷ 3
= 160 km/h
Duration that Tommy took to reach Town E after passing the boutique
= 240 ÷ 160
= 1.5 h
Duration that Paul took to reach Town E after passing the boutique
= 240 ÷ 80
= 3 h
Difference between the time they took to reach Town E
= 3 - 1.5
= 1.5 h
1 h = 60 min
1.5 h = 1.5 x 60 = 90 min
Tommy reached Town E 90 minutes earlier than Paul.
Answer(s): 90 min