At 10 15, Julian left Town Z for Town A, driving at a speed of 82 km/h. At 12 15, Bryan also left Town Z for Town A driving at a certain speed. Both of them did not change their speed throughout the journey. At 14 15, both of them passed a church that was 246 km away from Town A. How many minutes earlier did Bryan reach Town A than Julian?

Distance that Julian travelled
= 4 x 82
= 328 km

Distance between Town Z and Town A
= 328 + 246
= 574 km

Since Bryan passed the church at the same time as Julian, it means that Bryan travelled 328 km in 2 hours.

Bryan's speed during the journey
= 328 ÷ 2
= 164 km/h

Duration that Bryan took to reach Town A after passing the church
= 246 ÷ 164
= 1.5 h

Duration that Julian took to reach Town A after passing the church
= 246 ÷ 82
= 3 h

Difference between the time they took to reach Town A
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Bryan reached Town A 90 minutes earlier than Julian.

Answer(s): 90 min