At 10 20, Jack left Town U for Town V, driving at a speed of 92 km/h. At 11 20, Owen also left Town U for Town V driving at a certain speed. Both of them did not change their speed throughout the journey. At 15 20, both of them passed a market that was 184 km away from Town V. How many minutes earlier did Owen reach Town V than Jack?
Duration that Jack travelled from 10 20 to 15 20 = 5 h
Distance that Jack travelled
= 5 x 92
= 460 km
Distance between Town U and Town V
= 460 + 184
= 644 km
Since Owen passed the market at the same time as Jack, it means that Owen travelled 460 km in 4 hours.
Owen's speed during the journey
= 460 ÷ 4
= 115 km/h
Duration that Owen took to reach Town V after passing the market
= 184 ÷ 115
= 1.6 h
Duration that Jack took to reach Town V after passing the market
= 184 ÷ 92
= 2 h
Difference between the time they took to reach Town V
= 2 - 1.6
= 0.4 h
1 h = 60 min
0.4 h = 0.4 x 60 = 24 min
Owen reached Town V 24 minutes earlier than Jack.
Answer(s): 24 min