At 10 10, Tommy left Town D for Town E, driving at a speed of 66 km/h. At 13 10, Dylan also left Town D for Town E driving at a certain speed. Both of them did not change their speed throughout the journey. At 15 10, both of them passed a cafe that was 198 km away from Town E. How many minutes earlier did Dylan reach Town E than Tommy?
Duration that Tommy travelled from 10 10 to 15 10 = 5 h
Distance that Tommy travelled
= 5 x 66
= 330 km
Distance between Town D and Town E
= 330 + 198
= 528 km
Since Dylan passed the cafe at the same time as Tommy, it means that Dylan travelled 330 km in 2 hours.
Dylan's speed during the journey
= 330 ÷ 2
= 165 km/h
Duration that Dylan took to reach Town E after passing the cafe
= 198 ÷ 165
= 1.2 h
Duration that Tommy took to reach Town E after passing the cafe
= 198 ÷ 66
= 3 h
Difference between the time they took to reach Town E
= 3 - 1.2
= 1.8 h
1 h = 60 min
1.8 h = 1.8 x 60 = 108 min
Dylan reached Town E 108 minutes earlier than Tommy.
Answer(s): 108 min
