At 10 10, Reggie left Town G for Town H, driving at a speed of 86 km/h. At 12 10, Eric also left Town G for Town H driving at a certain speed. Both of them did not change their speed throughout the journey. At 14 10, both of them passed a boutique that was 258 km away from Town H. How many minutes earlier did Eric reach Town H than Reggie?

Distance that Reggie travelled
= 4 x 86
= 344 km

Distance between Town G and Town H
= 344 + 258
= 602 km

Since Eric passed the boutique at the same time as Reggie, it means that Eric travelled 344 km in 2 hours.

Eric's speed during the journey
= 344 ÷ 2
= 172 km/h

Duration that Eric took to reach Town H after passing the boutique
= 258 ÷ 172
= 1.5 h

Duration that Reggie took to reach Town H after passing the boutique
= 258 ÷ 86
= 3 h

Difference between the time they took to reach Town H
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Eric reached Town H 90 minutes earlier than Reggie.

Answer(s): 90 min