At 10 55, Brandon left Town A for Town B, driving at a speed of 62 km/h. At 13 55, Valen also left Town A for Town B driving at a certain speed. Both of them did not change their speed throughout the journey. At 15 55, both of them passed a cinema that was 248 km away from Town B. How many minutes earlier did Valen reach Town B than Brandon?

Distance that Brandon travelled
= 5 x 62
= 310 km

Distance between Town A and Town B
= 310 + 248
= 558 km

Since Valen passed the cinema at the same time as Brandon, it means that Valen travelled 310 km in 2 hours.

Valen's speed during the journey
= 310 ÷ 2
= 155 km/h

Duration that Valen took to reach Town B after passing the cinema
= 248 ÷ 155
= 1.6 h

Duration that Brandon took to reach Town B after passing the cinema
= 248 ÷ 62
= 4 h

Difference between the time they took to reach Town B
= 4 - 1.6
= 2.4 h

1 h = 60 min
2.4 h = 2.4 x 60 = 144 min

Valen reached Town B 144 minutes earlier than Brandon.

Answer(s): 144 min