At 14 10, Ethan left Town V for Town W, driving at a speed of 75 km/h. At 16 10, Michael also left Town V for Town W driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 10, both of them passed a school that was 150 km away from Town W. How many minutes earlier did Michael reach Town W than Ethan?
Duration that Ethan travelled from 14 10 to 19 10 = 5 h
Distance that Ethan travelled
= 5 x 75
= 375 km
Distance between Town V and Town W
= 375 + 150
= 525 km
Since Michael passed the school at the same time as Ethan, it means that Michael travelled 375 km in 3 hours.
Michael's speed during the journey
= 375 ÷ 3
= 125 km/h
Duration that Michael took to reach Town W after passing the school
= 150 ÷ 125
= 1.2 h
Duration that Ethan took to reach Town W after passing the school
= 150 ÷ 75
= 2 h
Difference between the time they took to reach Town W
= 2 - 1.2
= 0.8 h
1 h = 60 min
0.8 h = 0.8 x 60 = 48 min
Michael reached Town W 48 minutes earlier than Ethan.
Answer(s): 48 min