At 14 10, Archie left Town U for Town V, driving at a speed of 90 km/h. At 16 10, Pierre also left Town U for Town V driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 10, both of them passed a playground that was 180 km away from Town V. How many minutes earlier did Pierre reach Town V than Archie?

Distance that Archie travelled
= 5 x 90
= 450 km

Distance between Town U and Town V
= 450 + 180
= 630 km

Since Pierre passed the playground at the same time as Archie, it means that Pierre travelled 450 km in 3 hours.

Pierre's speed during the journey
= 450 ÷ 3
= 150 km/h

Duration that Pierre took to reach Town V after passing the playground
= 180 ÷ 150
= 1.2 h

Duration that Archie took to reach Town V after passing the playground
= 180 ÷ 90
= 2 h

Difference between the time they took to reach Town V
= 2 - 1.2
= 0.8 h

1 h = 60 min
0.8 h = 0.8 x 60 = 48 min

Pierre reached Town V 48 minutes earlier than Archie.

Answer(s): 48 min