At 13 45, Tom left Town Z for Town A, driving at a speed of 90 km/h. At 15 45, Perry also left Town Z for Town A driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 45, both of them passed a cafe that was 180 km away from Town A. How many minutes earlier did Perry reach Town A than Tom?
Duration that Tom travelled from 13 45 to 18 45 = 5 h
Distance that Tom travelled
= 5 x 90
= 450 km
Distance between Town Z and Town A
= 450 + 180
= 630 km
Since Perry passed the cafe at the same time as Tom, it means that Perry travelled 450 km in 3 hours.
Perry's speed during the journey
= 450 ÷ 3
= 150 km/h
Duration that Perry took to reach Town A after passing the cafe
= 180 ÷ 150
= 1.2 h
Duration that Tom took to reach Town A after passing the cafe
= 180 ÷ 90
= 2 h
Difference between the time they took to reach Town A
= 2 - 1.2
= 0.8 h
1 h = 60 min
0.8 h = 0.8 x 60 = 48 min
Perry reached Town A 48 minutes earlier than Tom.
Answer(s): 48 min