At 10 35, Michael left Town U for Town V, driving at a speed of 99 km/h. At 11 35, George also left Town U for Town V driving at a certain speed. Both of them did not change their speed throughout the journey. At 14 35, both of them passed a cafe that was 198 km away from Town V. How many minutes earlier did George reach Town V than Michael?

Distance that Michael travelled
= 4 x 99
= 396 km

Distance between Town U and Town V
= 396 + 198
= 594 km

Since George passed the cafe at the same time as Michael, it means that George travelled 396 km in 3 hours.

George's speed during the journey
= 396 ÷ 3
= 132 km/h

Duration that George took to reach Town V after passing the cafe
= 198 ÷ 132
= 1.5 h

Duration that Michael took to reach Town V after passing the cafe
= 198 ÷ 99
= 2 h

Difference between the time they took to reach Town V
= 2 - 1.5
= 0.5 h

1 h = 60 min
0.5 h = 0.5 x 60 = 30 min

George reached Town V 30 minutes earlier than Michael.

Answer(s): 30 min