At 11 25, Ben left Town B for Town C, driving at a speed of 63 km/h. At 12 25, Seth also left Town B for Town C driving at a certain speed. Both of them did not change their speed throughout the journey. At 15 25, both of them passed a school that was 126 km away from Town C. How many minutes earlier did Seth reach Town C than Ben?
Duration that Ben travelled from 11 25 to 15 25 = 4 h
Distance that Ben travelled
= 4 x 63
= 252 km
Distance between Town B and Town C
= 252 + 126
= 378 km
Since Seth passed the school at the same time as Ben, it means that Seth travelled 252 km in 3 hours.
Seth's speed during the journey
= 252 ÷ 3
= 84 km/h
Duration that Seth took to reach Town C after passing the school
= 126 ÷ 84
= 1.5 h
Duration that Ben took to reach Town C after passing the school
= 126 ÷ 63
= 2 h
Difference between the time they took to reach Town C
= 2 - 1.5
= 0.5 h
1 h = 60 min
0.5 h = 0.5 x 60 = 30 min
Seth reached Town C 30 minutes earlier than Ben.
Answer(s): 30 min
