At 12 20, Owen left Town Z for Town A, driving at a speed of 89 km/h. At 15 20, Tom also left Town Z for Town A driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 20, both of them passed a grocery store that was 267 km away from Town A. How many minutes earlier did Tom reach Town A than Owen?

Distance that Owen travelled
= 6 x 89
= 534 km

Distance between Town Z and Town A
= 534 + 267
= 801 km

Since Tom passed the grocery store at the same time as Owen, it means that Tom travelled 534 km in 3 hours.

Tom's speed during the journey
= 534 ÷ 3
= 178 km/h

Duration that Tom took to reach Town A after passing the grocery store
= 267 ÷ 178
= 1.5 h

Duration that Owen took to reach Town A after passing the grocery store
= 267 ÷ 89
= 3 h

Difference between the time they took to reach Town A
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Tom reached Town A 90 minutes earlier than Owen.

Answer(s): 90 min