At 14 15, Charlie left Town Z for Town A, driving at a speed of 63 km/h. At 16 15, Bryan also left Town Z for Town A driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 15, both of them passed a bakery that was 189 km away from Town A. How many minutes earlier did Bryan reach Town A than Charlie?

Distance that Charlie travelled
= 4 x 63
= 252 km

Distance between Town Z and Town A
= 252 + 189
= 441 km

Since Bryan passed the bakery at the same time as Charlie, it means that Bryan travelled 252 km in 2 hours.

Bryan's speed during the journey
= 252 ÷ 2
= 126 km/h

Duration that Bryan took to reach Town A after passing the bakery
= 189 ÷ 126
= 1.5 h

Duration that Charlie took to reach Town A after passing the bakery
= 189 ÷ 63
= 3 h

Difference between the time they took to reach Town A
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Bryan reached Town A 90 minutes earlier than Charlie.

Answer(s): 90 min