At 14 20, Perry left Town Y for Town Z, driving at a speed of 66 km/h. At 16 20, Vaidev also left Town Y for Town Z driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 20, both of them passed a bakery that was 198 km away from Town Z. How many minutes earlier did Vaidev reach Town Z than Perry?

Distance that Perry travelled
= 5 x 66
= 330 km

Distance between Town Y and Town Z
= 330 + 198
= 528 km

Since Vaidev passed the bakery at the same time as Perry, it means that Vaidev travelled 330 km in 3 hours.

Vaidev's speed during the journey
= 330 ÷ 3
= 110 km/h

Duration that Vaidev took to reach Town Z after passing the bakery
= 198 ÷ 110
= 1.8 h

Duration that Perry took to reach Town Z after passing the bakery
= 198 ÷ 66
= 3 h

Difference between the time they took to reach Town Z
= 3 - 1.8
= 1.2 h

1 h = 60 min
1.2 h = 1.2 x 60 = 72 min

Vaidev reached Town Z 72 minutes earlier than Perry.

Answer(s): 72 min