At 13 35, Asher left Town Z for Town A, driving at a speed of 85 km/h. At 15 35, Albert also left Town Z for Town A driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 35, both of them passed a park that was 255 km away from Town A. How many minutes earlier did Albert reach Town A than Asher?

Distance that Asher travelled
= 4 x 85
= 340 km

Distance between Town Z and Town A
= 340 + 255
= 595 km

Since Albert passed the park at the same time as Asher, it means that Albert travelled 340 km in 2 hours.

Albert's speed during the journey
= 340 ÷ 2
= 170 km/h

Duration that Albert took to reach Town A after passing the park
= 255 ÷ 170
= 1.5 h

Duration that Asher took to reach Town A after passing the park
= 255 ÷ 85
= 3 h

Difference between the time they took to reach Town A
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Albert reached Town A 90 minutes earlier than Asher.

Answer(s): 90 min