At 12 30, Ian left Town S for Town T, driving at a speed of 63 km/h. At 13 30, Oscar also left Town S for Town T driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 30, both of them passed a cafe that was 126 km away from Town T. How many minutes earlier did Oscar reach Town T than Ian?
Duration that Ian travelled from 12 30 to 16 30 = 4 h
Distance that Ian travelled
= 4 x 63
= 252 km
Distance between Town S and Town T
= 252 + 126
= 378 km
Since Oscar passed the cafe at the same time as Ian, it means that Oscar travelled 252 km in 3 hours.
Oscar's speed during the journey
= 252 ÷ 3
= 84 km/h
Duration that Oscar took to reach Town T after passing the cafe
= 126 ÷ 84
= 1.5 h
Duration that Ian took to reach Town T after passing the cafe
= 126 ÷ 63
= 2 h
Difference between the time they took to reach Town T
= 2 - 1.5
= 0.5 h
1 h = 60 min
0.5 h = 0.5 x 60 = 30 min
Oscar reached Town T 30 minutes earlier than Ian.
Answer(s): 30 min
