At 14 10, Nick left Town D for Town E, driving at a speed of 68 km/h. At 15 10, Reggie also left Town D for Town E driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 10, both of them passed a mosque that was 136 km away from Town E. How many minutes earlier did Reggie reach Town E than Nick?

Distance that Nick travelled
= 5 x 68
= 340 km

Distance between Town D and Town E
= 340 + 136
= 476 km

Since Reggie passed the mosque at the same time as Nick, it means that Reggie travelled 340 km in 4 hours.

Reggie's speed during the journey
= 340 ÷ 4
= 85 km/h

Duration that Reggie took to reach Town E after passing the mosque
= 136 ÷ 85
= 1.6 h

Duration that Nick took to reach Town E after passing the mosque
= 136 ÷ 68
= 2 h

Difference between the time they took to reach Town E
= 2 - 1.6
= 0.4 h

1 h = 60 min
0.4 h = 0.4 x 60 = 24 min

Reggie reached Town E 24 minutes earlier than Nick.

Answer(s): 24 min