At 12 10, Ben left Town A for Town B, driving at a speed of 96 km/h. At 13 10, Jack also left Town A for Town B driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 10, both of them passed a market that was 192 km away from Town B. How many minutes earlier did Jack reach Town B than Ben?
Duration that Ben travelled from 12 10 to 17 10 = 5 h
Distance that Ben travelled
= 5 x 96
= 480 km
Distance between Town A and Town B
= 480 + 192
= 672 km
Since Jack passed the market at the same time as Ben, it means that Jack travelled 480 km in 4 hours.
Jack's speed during the journey
= 480 ÷ 4
= 120 km/h
Duration that Jack took to reach Town B after passing the market
= 192 ÷ 120
= 1.6 h
Duration that Ben took to reach Town B after passing the market
= 192 ÷ 96
= 2 h
Difference between the time they took to reach Town B
= 2 - 1.6
= 0.4 h
1 h = 60 min
0.4 h = 0.4 x 60 = 24 min
Jack reached Town B 24 minutes earlier than Ben.
Answer(s): 24 min
