At 10 15, Nick left Town E for Town F, driving at a speed of 66 km/h. At 13 15, Will also left Town E for Town F driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 15, both of them passed a cinema that was 198 km away from Town F. How many minutes earlier did Will reach Town F than Nick?

Distance that Nick travelled
= 6 x 66
= 396 km

Distance between Town E and Town F
= 396 + 198
= 594 km

Since Will passed the cinema at the same time as Nick, it means that Will travelled 396 km in 3 hours.

Will's speed during the journey
= 396 ÷ 3
= 132 km/h

Duration that Will took to reach Town F after passing the cinema
= 198 ÷ 132
= 1.5 h

Duration that Nick took to reach Town F after passing the cinema
= 198 ÷ 66
= 3 h

Difference between the time they took to reach Town F
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Will reached Town F 90 minutes earlier than Nick.

Answer(s): 90 min