At 12 55, Flynn left Town N for Town P, driving at a speed of 88 km/h. At 15 55, Bryan also left Town N for Town P driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 55, both of them passed a school that was 264 km away from Town P. How many minutes earlier did Bryan reach Town P than Flynn?

Distance that Flynn travelled
= 6 x 88
= 528 km

Distance between Town N and Town P
= 528 + 264
= 792 km

Since Bryan passed the school at the same time as Flynn, it means that Bryan travelled 528 km in 3 hours.

Bryan's speed during the journey
= 528 ÷ 3
= 176 km/h

Duration that Bryan took to reach Town P after passing the school
= 264 ÷ 176
= 1.5 h

Duration that Flynn took to reach Town P after passing the school
= 264 ÷ 88
= 3 h

Difference between the time they took to reach Town P
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Bryan reached Town P 90 minutes earlier than Flynn.

Answer(s): 90 min