At 12 15, Lee left Town N for Town P, driving at a speed of 62 km/h. At 15 15, Jenson also left Town N for Town P driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 15, both of them passed a playground that was 186 km away from Town P. How many minutes earlier did Jenson reach Town P than Lee?

Distance that Lee travelled
= 6 x 62
= 372 km

Distance between Town N and Town P
= 372 + 186
= 558 km

Since Jenson passed the playground at the same time as Lee, it means that Jenson travelled 372 km in 3 hours.

Jenson's speed during the journey
= 372 ÷ 3
= 124 km/h

Duration that Jenson took to reach Town P after passing the playground
= 186 ÷ 124
= 1.5 h

Duration that Lee took to reach Town P after passing the playground
= 186 ÷ 62
= 3 h

Difference between the time they took to reach Town P
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Jenson reached Town P 90 minutes earlier than Lee.

Answer(s): 90 min