At 13 15, Xavier left Town N for Town P, driving at a speed of 93 km/h. At 15 15, Sean also left Town N for Town P driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 15, both of them passed a bakery that was 186 km away from Town P. How many minutes earlier did Sean reach Town P than Xavier?

Distance that Xavier travelled
= 5 x 93
= 465 km

Distance between Town N and Town P
= 465 + 186
= 651 km

Since Sean passed the bakery at the same time as Xavier, it means that Sean travelled 465 km in 3 hours.

Sean's speed during the journey
= 465 ÷ 3
= 155 km/h

Duration that Sean took to reach Town P after passing the bakery
= 186 ÷ 155
= 1.2 h

Duration that Xavier took to reach Town P after passing the bakery
= 186 ÷ 93
= 2 h

Difference between the time they took to reach Town P
= 2 - 1.2
= 0.8 h

1 h = 60 min
0.8 h = 0.8 x 60 = 48 min

Sean reached Town P 48 minutes earlier than Xavier.

Answer(s): 48 min