At 10 15, Japheth left Town J for Town K, driving at a speed of 62 km/h. At 12 15, Brandon also left Town J for Town K driving at a certain speed. Both of them did not change their speed throughout the journey. At 14 15, both of them passed a church that was 186 km away from Town K. How many minutes earlier did Brandon reach Town K than Japheth?

Distance that Japheth travelled
= 4 x 62
= 248 km

Distance between Town J and Town K
= 248 + 186
= 434 km

Since Brandon passed the church at the same time as Japheth, it means that Brandon travelled 248 km in 2 hours.

Brandon's speed during the journey
= 248 ÷ 2
= 124 km/h

Duration that Brandon took to reach Town K after passing the church
= 186 ÷ 124
= 1.5 h

Duration that Japheth took to reach Town K after passing the church
= 186 ÷ 62
= 3 h

Difference between the time they took to reach Town K
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Brandon reached Town K 90 minutes earlier than Japheth.

Answer(s): 90 min