At 11 25, Lee left Town A for Town B, driving at a speed of 72 km/h. At 13 25, Ivan also left Town A for Town B driving at a certain speed. Both of them did not change their speed throughout the journey. At 15 25, both of them passed a grocery store that was 216 km away from Town B. How many minutes earlier did Ivan reach Town B than Lee?

Distance that Lee travelled
= 4 x 72
= 288 km

Distance between Town A and Town B
= 288 + 216
= 504 km

Since Ivan passed the grocery store at the same time as Lee, it means that Ivan travelled 288 km in 2 hours.

Ivan's speed during the journey
= 288 ÷ 2
= 144 km/h

Duration that Ivan took to reach Town B after passing the grocery store
= 216 ÷ 144
= 1.5 h

Duration that Lee took to reach Town B after passing the grocery store
= 216 ÷ 72
= 3 h

Difference between the time they took to reach Town B
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Ivan reached Town B 90 minutes earlier than Lee.

Answer(s): 90 min