At 13 25, Ken left Town F for Town G, driving at a speed of 66 km/h. At 16 25, Albert also left Town F for Town G driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 25, both of them passed a bistro that was 264 km away from Town G. How many minutes earlier did Albert reach Town G than Ken?
Duration that Ken travelled from 13 25 to 18 25 = 5 h
Distance that Ken travelled
= 5 x 66
= 330 km
Distance between Town F and Town G
= 330 + 264
= 594 km
Since Albert passed the bistro at the same time as Ken, it means that Albert travelled 330 km in 2 hours.
Albert's speed during the journey
= 330 ÷ 2
= 165 km/h
Duration that Albert took to reach Town G after passing the bistro
= 264 ÷ 165
= 1.6 h
Duration that Ken took to reach Town G after passing the bistro
= 264 ÷ 66
= 4 h
Difference between the time they took to reach Town G
= 4 - 1.6
= 2.4 h
1 h = 60 min
2.4 h = 2.4 x 60 = 144 min
Albert reached Town G 144 minutes earlier than Ken.
Answer(s): 144 min
