At 14 10, Peter left Town Z for Town A, driving at a speed of 90 km/h. At 16 10, Warren also left Town Z for Town A driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 10, both of them passed a florist that was 270 km away from Town A. How many minutes earlier did Warren reach Town A than Peter?
Duration that Peter travelled from 14 10 to 19 10 = 5 h
Distance that Peter travelled
= 5 x 90
= 450 km
Distance between Town Z and Town A
= 450 + 270
= 720 km
Since Warren passed the florist at the same time as Peter, it means that Warren travelled 450 km in 3 hours.
Warren's speed during the journey
= 450 ÷ 3
= 150 km/h
Duration that Warren took to reach Town A after passing the florist
= 270 ÷ 150
= 1.8 h
Duration that Peter took to reach Town A after passing the florist
= 270 ÷ 90
= 3 h
Difference between the time they took to reach Town A
= 3 - 1.8
= 1.2 h
1 h = 60 min
1.2 h = 1.2 x 60 = 72 min
Warren reached Town A 72 minutes earlier than Peter.
Answer(s): 72 min