At 12 25, Luke left Town Z for Town A, driving at a speed of 88 km/h. At 13 25, Asher also left Town Z for Town A driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 25, both of them passed a school that was 176 km away from Town A. How many minutes earlier did Asher reach Town A than Luke?

Distance that Luke travelled
= 5 x 88
= 440 km

Distance between Town Z and Town A
= 440 + 176
= 616 km

Since Asher passed the school at the same time as Luke, it means that Asher travelled 440 km in 4 hours.

Asher's speed during the journey
= 440 ÷ 4
= 110 km/h

Duration that Asher took to reach Town A after passing the school
= 176 ÷ 110
= 1.6 h

Duration that Luke took to reach Town A after passing the school
= 176 ÷ 88
= 2 h

Difference between the time they took to reach Town A
= 2 - 1.6
= 0.4 h

1 h = 60 min
0.4 h = 0.4 x 60 = 24 min

Asher reached Town A 24 minutes earlier than Luke.

Answer(s): 24 min