At 11 35, Warren left Town A for Town B, driving at a speed of 83 km/h. At 14 35, Will also left Town A for Town B driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 35, both of them passed a florist that was 249 km away from Town B. How many minutes earlier did Will reach Town B than Warren?

Distance that Warren travelled
= 6 x 83
= 498 km

Distance between Town A and Town B
= 498 + 249
= 747 km

Since Will passed the florist at the same time as Warren, it means that Will travelled 498 km in 3 hours.

Will's speed during the journey
= 498 ÷ 3
= 166 km/h

Duration that Will took to reach Town B after passing the florist
= 249 ÷ 166
= 1.5 h

Duration that Warren took to reach Town B after passing the florist
= 249 ÷ 83
= 3 h

Difference between the time they took to reach Town B
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Will reached Town B 90 minutes earlier than Warren.

Answer(s): 90 min