At 10 10, Sam left Town A for Town B, driving at a speed of 69 km/h. At 12 10, Michael also left Town A for Town B driving at a certain speed. Both of them did not change their speed throughout the journey. At 14 10, both of them passed a farm that was 207 km away from Town B. How many minutes earlier did Michael reach Town B than Sam?

Distance that Sam travelled
= 4 x 69
= 276 km

Distance between Town A and Town B
= 276 + 207
= 483 km

Since Michael passed the farm at the same time as Sam, it means that Michael travelled 276 km in 2 hours.

Michael's speed during the journey
= 276 ÷ 2
= 138 km/h

Duration that Michael took to reach Town B after passing the farm
= 207 ÷ 138
= 1.5 h

Duration that Sam took to reach Town B after passing the farm
= 207 ÷ 69
= 3 h

Difference between the time they took to reach Town B
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Michael reached Town B 90 minutes earlier than Sam.

Answer(s): 90 min