At 14 15, Carl left Town T for Town U, driving at a speed of 69 km/h. At 16 15, Xavier also left Town T for Town U driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 15, both of them passed a temple that was 138 km away from Town U. How many minutes earlier did Xavier reach Town U than Carl?

Distance that Carl travelled
= 5 x 69
= 345 km

Distance between Town T and Town U
= 345 + 138
= 483 km

Since Xavier passed the temple at the same time as Carl, it means that Xavier travelled 345 km in 3 hours.

Xavier's speed during the journey
= 345 ÷ 3
= 115 km/h

Duration that Xavier took to reach Town U after passing the temple
= 138 ÷ 115
= 1.2 h

Duration that Carl took to reach Town U after passing the temple
= 138 ÷ 69
= 2 h

Difference between the time they took to reach Town U
= 2 - 1.2
= 0.8 h

1 h = 60 min
0.8 h = 0.8 x 60 = 48 min

Xavier reached Town U 48 minutes earlier than Carl.

Answer(s): 48 min