At 2.20 p.m., Penelope and Asher left Hotel L for Hotel M at average speeds of 68 km/h and 57 km/h respectively. Upon reaching Hotel M, Penelope rested for 10 minutes. She then headed back for Hotel L at an average speed of 68 km/h along the same route. Asher and Penelope met each other on their way at 6 p.m.
- How much more distance had Penelope covered than Asher when they met on their way?
- How far apart were Hotel L and Hotel M? Express your answer in mixed number.
(a)
Duration from 2.20 p.m. to 6 p.m. = 3 h 40 min = 3
23 h
Duration from 2.20 p.m. to 6 p.m. without 10 min rest = 3 h 30 min = 3
12 h
60 min = 1 h
40 min =
4060 =
23 h
30 min =
3060 =
12 h
Distance covered by Penelope
= 68 x 3
12= 68 x
72 = 238 km
Distance covered by Asher
= 57 x 3
12= 57 x
72= 209 km
Distance that Penelope covered more than Asher
= 238 - 209
= 29 km
(b)
Distance between Hotel L and Hotel M
= (238 + 209) ÷ 2
= 447 ÷ 2
= 223
12 km
Answer(s): (a) 29 km; (b) 223
12 km