At 1.30 p.m., Usha and Will left Hotel J for Hotel K at average speeds of 88 km/h and 50 km/h respectively. Upon reaching Hotel K, Usha rested for 15 minutes. She then headed back for Hotel J at an average speed of 88 km/h along the same route. Will and Usha met each other on their way at 5 p.m.
- How much more distance had Usha covered than Will when they met on their way?
- How far apart were Hotel J and Hotel K? Express your answer in mixed number.
(a)
Duration from 1.30 p.m. to 5 p.m. = 3 h 30 min = 3
12 h
Duration from 1.30 p.m. to 5 p.m. without 15 min rest = 3 h 15 min = 3
14 h
60 min = 1 h
30 min =
3060 =
12 h
15 min =
1560 =
14 h
Distance covered by Usha
= 88 x 3
14= 88 x
134 = 286 km
Distance covered by Will
= 50 x 3
14= 50 x
134= 175 km
Distance that Usha covered more than Will
= 286 - 175
= 111 km
(b)
Distance between Hotel J and Hotel K
= (286 + 175) ÷ 2
= 461 ÷ 2
= 230
12 km
Answer(s): (a) 111 km; (b) 230
12 km