At 5.30 p.m., Usha and Ken left Hotel R for Hotel S at average speeds of 96 km/h and 58 km/h respectively. Upon reaching Hotel S, Usha rested for 10 minutes. She then headed back for Hotel R at an average speed of 96 km/h along the same route. Ken and Usha met each other on their way at 9 p.m.
- How much more distance had Usha covered than Ken when they met on their way?
- How far apart were Hotel R and Hotel S? Express your answer in mixed number.
(a)
Duration from 5.30 p.m. to 9 p.m. = 3 h 30 min = 3
12 h
Duration from 5.30 p.m. to 9 p.m. without 10 min rest = 3 h 20 min = 3
13 h
60 min = 1 h
30 min =
3060 =
12 h
20 min =
2060 =
13 h
Distance covered by Usha
= 96 x 3
13= 96 x
103 = 320 km
Distance covered by Ken
= 58 x 3
13= 58 x
103= 203 km
Distance that Usha covered more than Ken
= 320 - 203
= 117 km
(b)
Distance between Hotel R and Hotel S
= (320 + 203) ÷ 2
= 523 ÷ 2
= 261
12 km
Answer(s): (a) 117 km; (b) 261
12 km