At 2.30 p.m., Shiyun and Ivan left Hotel D for Hotel E at average speeds of 99 km/h and 62 km/h respectively. Upon reaching Hotel E, Shiyun rested for 10 minutes. She then headed back for Hotel D at an average speed of 99 km/h along the same route. Ivan and Shiyun met each other on their way at 6 p.m.
- How much more distance had Shiyun covered than Ivan when they met on their way?
- How far apart were Hotel D and Hotel E? Express your answer in mixed number.
(a)
Duration from 2.30 p.m. to 6 p.m. = 3 h 30 min = 3
12 h
Duration from 2.30 p.m. to 6 p.m. without 10 min rest = 3 h 20 min = 3
13 h
60 min = 1 h
30 min =
3060 =
12 h
20 min =
2060 =
13 h
Distance covered by Shiyun
= 99 x 3
13= 99 x
103 = 330 km
Distance covered by Ivan
= 62 x 3
13= 62 x
103= 217 km
Distance that Shiyun covered more than Ivan
= 330 - 217
= 113 km
(b)
Distance between Hotel D and Hotel E
= (330 + 217) ÷ 2
= 547 ÷ 2
= 273
12 km
Answer(s): (a) 113 km; (b) 273
12 km