At 5.20 p.m., Jaslyn and Luis left Hotel V for Hotel W at average speeds of 92 km/h and 75 km/h respectively. Upon reaching Hotel W, Jaslyn rested for 10 minutes. She then headed back for Hotel V at an average speed of 92 km/h along the same route. Luis and Jaslyn met each other on their way at 9 p.m.

1. How much more distance had Jaslyn covered than Luis when they met on their way?
2. How far apart were Hotel V and Hotel W? Express your answer in mixed number.

(a)
Duration from 5.20 p.m. to 9 p.m. = 3 h 40 min = 3²₃ h
Duration from 5.20 p.m. to 9 p.m. without 10 min rest = 3 h 30 min = 3¹₂ h

60 min = 1 h
40 min = ⁴⁰₆₀ = ²₃ h
30 min = ³⁰₆₀ = ¹₂ h


Distance covered by Jaslyn
= 92 x 3¹₂
= 92 x ⁷₂ 
= 322 km

Distance covered by Luis
= 75 x 3¹₂
= 75 x ⁷₂
= 275 km

Distance that Jaslyn covered more than Luis
= 322 - 275
= 47 km

(b)
Distance between Hotel V and Hotel W
= (322 + 275) ÷ 2
= 597 ÷ 2
= 298¹₂ km

Answer(s): (a) 47 km; (b) 298¹₂ km