At 2.30 p.m., Shannon and Sean left Hotel P for Hotel Q at average speeds of 81 km/h and 50 km/h respectively. Upon reaching Hotel Q, Shannon rested for 10 minutes. She then headed back for Hotel P at an average speed of 81 km/h along the same route. Sean and Shannon met each other on their way at 6 p.m.
- How much more distance had Shannon covered than Sean when they met on their way?
- How far apart were Hotel P and Hotel Q? Express your answer in mixed number.
(a)
Duration from 2.30 p.m. to 6 p.m. = 3 h 30 min = 3
12 h
Duration from 2.30 p.m. to 6 p.m. without 10 min rest = 3 h 20 min = 3
13 h
60 min = 1 h
30 min =
3060 =
12 h
20 min =
2060 =
13 h
Distance covered by Shannon
= 81 x 3
13= 81 x
103 = 270 km
Distance covered by Sean
= 50 x 3
13= 50 x
103= 175 km
Distance that Shannon covered more than Sean
= 270 - 175
= 95 km
(b)
Distance between Hotel P and Hotel Q
= (270 + 175) ÷ 2
= 445 ÷ 2
= 222
12 km
Answer(s): (a) 95 km; (b) 222
12 km