Yoko started jogging from the temple to the garden at a speed of 105 m/min at 5 a.m. Her cousin started jogging from the temple later. They were beside each other at 5.36 a.m. and her cousin reached the garden at 6 a.m. while Yoko was still 1800 m away. If both of them travelled at a constant speed throughout the journey, what time did her cousin leave the temple?
1 h = 60 min

From 5 a.m. to 6 a.m. = 1 h
From 5.36 a.m. to 6 a.m. = 24 min

Distance between the temple and the garden
= 60 x 105 + 1800
= 6300 + 1800
= 8100 m

Distance that Yoko's cousin had to cover to catch up with Yoko
= 36 x 105
= 3780 m

Distance that Yoko's cousin travelled to the garden after catching up with Yoko
= 8100 - 3780
= 4320 m

Since Yoko's cousin jogged 4320 m in 36 min,
Yoko's cousin average speed
= 4320 ÷ 24
= 180 m/min

Duration that Yoko's cousin took to jog to the garden
= 8100 ÷ 180
= 45 min

Time that Yoko's cousin left the temple:
45 min before 6 a.m. = 5.15 a.m.

Answer(s): 5.15 a.m.